program to print the sum of even and odd number in 10 numbers in array in c-programming
In this program we will now takes 10 numbers form the user and print the sum of even and odd number and also print the even and odd in c-programming.
#include<stdio.h>
#include<conio.h>
void main()
{
int a[10],i,even,odd,sum=0,evensum=0,oddsum=0;
printf("enter the 10 number:-");
for(i=0;i<=9;i++){
scanf("%d",&a[i]);
}
for(i=0;i<=9;i++){
sum=sum+a[i];
if(a[i]%2==0){
printf("even number is %d\n",a[i]);
evensum=evensum+a[i];
}
else{
printf("odd number is %d\n",a[i]);
oddsum=oddsum+a[i];
}
}
printf("\n the sum of even number is %d",evensum);
printf("\n the sum of odd number is %d",oddsum);
printf("\n the sum of the number is %d",sum);
getch();
}
#include<conio.h>
void main()
{
int a[10],i,even,odd,sum=0,evensum=0,oddsum=0;
printf("enter the 10 number:-");
for(i=0;i<=9;i++){
scanf("%d",&a[i]);
}
for(i=0;i<=9;i++){
sum=sum+a[i];
if(a[i]%2==0){
printf("even number is %d\n",a[i]);
evensum=evensum+a[i];
}
else{
printf("odd number is %d\n",a[i]);
oddsum=oddsum+a[i];
}
}
printf("\n the sum of even number is %d",evensum);
printf("\n the sum of odd number is %d",oddsum);
printf("\n the sum of the number is %d",sum);
getch();
}
output:-
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