c-program to find all the factors of n natural number in c-language.

c-program to  find all the factor of  n natural number 

The numbers that are completely divisible by the given value (it means the remainder should be 0) called factors of a given number in c. lets us see how to write a program in c-program

In this program ,we will calculate the factor of  a number by taking value by the user and display the factor of the number .

Alogrithm

1. input number from the user . store it in variable 'n'.

2. run a loop form 1 to n , increment 1 in each iteration. for(i=1;i<=-n;i++);

3. for each iteration ,it check the condition i,e if(n%i==0)  then i is  a factor of n.

#include<stdio.h>
#include<conio.h>
void main()
{
    int i,n;
    printf("enter the number");
    scanf("%d",&n);
    for(i=1;i<=n;i++)
    {
        if(n%i==0)
        printf("%d ",i);
    }
    getch();
}

output:- n=36
  
  1,2,3,4,6,9.12,18,36

For more c-programming example:-

.c-program to calculate the sum of the two numbers